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Can anyone help with this homework question? I will attach a document.
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\[h(x)=4(3f(x)-g(x))^\left( 1/2 \right)\]
take the derivative (will be using the chain rule)
\[h \prime(x)=(1/2)(4)(3f(x)-g(x))^\left( -1/2 \right)(3f \prime(x)-g \prime(x))\] now sub x=12 \[h \prime(12)=(1/2)(4)(3f(12)-g(12))^\left( -1/2 \right)(3f \prime(12)-g \prime(12))\]
\[h \prime (12)=2(3 * 4-8)^\left( -1/2 \right)(3*15--5)\] \[h \prime (12)=2(12-8)^\left( -1/2 \right)(45+5)\] \[h \prime (12)=2(4)^\left( -1/2 \right)(50)\] \[h \prime (12)=2(1/2)(50)\] \[h \prime (12)=(50)\]
Thank you!
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I wrote the steps out to help you study it...... :)
Yes, that is awesome! It really helps to see it step by step.
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