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Mathematics 7 Online
OpenStudy (anonymous):

If g(x)=3+x+2e^x, find g^(−)1(5)

OpenStudy (anonymous):

its find g^(-1)(5)

OpenStudy (anonymous):

OpenStudy (anonymous):

Is that what you are looking for

OpenStudy (anonymous):

no

OpenStudy (anonymous):

what it is then

OpenStudy (anonymous):

OpenStudy (anonymous):

You have an interesting handwriting.

OpenStudy (anonymous):

Is the answer zero?

OpenStudy (anonymous):

I mean, it's a no-brainer if what he means with g^(-1)(5) is \(g^{-1}(5)\). That is, the inverse function of \(g\) evaluated at \(5\). Check that \(g(0)=5\). Therefore, \(g'(5)=0\).

OpenStudy (anonymous):

I meant \(g^{-1}\) not \(g'\).

OpenStudy (anonymous):

Agreed. that should be the answer if he meant the inverse function.

OpenStudy (anonymous):

the answer is zero thanks for the help

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