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Hey can someone help me with this?
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I need help with part b
f(x)=[x]-{x}+1
Slaibaak what happenned lol
\[s_2=\frac{1}{2}\] \[s_3=2\]
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YAY this awesome :D Thanks u r really nice
[x] means greatest integer function {x} means fractional part function
lol obviously i didnt follow haha its 4:30 am
to get \[s_n = {1 \over f({s_{n-1})}} \] Therefore: \[s_2 = {1 \over f({s_1})} ={1 \over f(1)} = {1 \over {1 + (1-0)}} = {1 \over 2}\] Now you do the same for s_3, since you have s_2 Sorry, I took long, had to do something first
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Just to show: \[s_3 = {1 \over f({1 \over 2}) } = {1 \over 0 + (1- {1 \over 2})} = 2\]
i think i get it
:D
Thanks Slaaibak that was helpful :D
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