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Mathematics 9 Online
OpenStudy (anonymous):

Hey can someone help me with this?

OpenStudy (anonymous):

OpenStudy (anonymous):

I need help with part b

OpenStudy (anonymous):

f(x)=[x]-{x}+1

OpenStudy (anonymous):

Slaibaak what happenned lol

OpenStudy (anonymous):

\[s_2=\frac{1}{2}\] \[s_3=2\]

OpenStudy (anonymous):

Find similarly other terms

OpenStudy (anonymous):

YAY this awesome :D Thanks u r really nice

OpenStudy (anonymous):

[x] means greatest integer function {x} means fractional part function

OpenStudy (anonymous):

lol obviously i didnt follow haha its 4:30 am

OpenStudy (slaaibak):

to get \[s_n = {1 \over f({s_{n-1})}} \] Therefore: \[s_2 = {1 \over f({s_1})} ={1 \over f(1)} = {1 \over {1 + (1-0)}} = {1 \over 2}\] Now you do the same for s_3, since you have s_2 Sorry, I took long, had to do something first

OpenStudy (slaaibak):

Just to show: \[s_3 = {1 \over f({1 \over 2}) } = {1 \over 0 + (1- {1 \over 2})} = 2\]

OpenStudy (anonymous):

i think i get it

OpenStudy (slaaibak):

:D

OpenStudy (anonymous):

Thanks Slaaibak that was helpful :D

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