Electrical Physics

A metallic wire of length=30m & 0.3cm^2 cross-sectional area is made from material of resistivity =5*10^-7 ohm.m.
calculate the current intensity flowing through this wire ,when it is connected in series with resistance= 8.5 ohm & battery of E.M.F=18v & it's internal resistance=1 ohm

Question

Electrical Physics  

A metallic wire of length=30m & 0.3cm^2          cross-sectional area is made from material of resistivity =5*10^-7 ohm.m.
calculate the current intensity flowing through this wire ,when it is connected in series with resistance= 8.5 ohm & battery of E.M.F=18v &  it's internal resistance=1 ohm

anonymous · Answer

http://hyperphysics.phy-astr.gsu.edu/hbase/hframe.html

jamesj · Answer

Just posting a generic link isn't very helpful.

JopHP, you need the formula for resistance in this case.  Do you know it?

jamesj · Answer

It is
$$ R = \frac{\rho L}{A} $$ where
$ \rho = $ resistivity
$ L = $ length
$ A = $ cross-sectional area