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Physics 20 Online
OpenStudy (anonymous):

find the value of current at X and its direction. Diagram is in attachment..help guys..

OpenStudy (anonymous):

OpenStudy (anonymous):

The internet is a beautiful thing!! http://hyperphysics.phy-astr.gsu.edu/hbase/hframe.html

OpenStudy (anonymous):

innit :)

OpenStudy (anonymous):

hey cristie can you solve it for me ??

OpenStudy (anonymous):

@deep eyes, this site is to gain knowledge. all will give ideas. we should solve by our own. then only we can improve.

OpenStudy (anonymous):

itried thousand tymes but still can't get it !!

OpenStudy (anonymous):

if moderator was here ..he could 've solved it !!

OpenStudy (anonymous):

http://hyperphysics.phy-astr.gsu.edu/hbase/hframe.html see this link

OpenStudy (anonymous):

try by this one

OpenStudy (stormfire1):

You have to use Kirchoff's Voltage and current laws to develop 3 equations. First draw in some current directions...what you choose for directions doesn't really matter as long as you stick with them throughout the problem. |dw:1330869214708:dw| Now go through each loop to make the equations. Using Kirchoff's voltage law you get these two equations: 4V=20*I2 + 20 * I1 10V = 20*I2 + 80*I3 Using Kirchoff's current law you get this node equation: I1 + I3 = I2 Now you have 3 equations with 3 unknowns. You can either solve them by hand or use your calculator to solve the matrix. The answers will be: I1 = 60 mA I2 = 140 mA I3 = 90 mA I2 is the middle current and since it's positive, the direction we chose to solve the problem was correct. If it were negative, the direction would have to be reversed.

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