Question

Current Electricity

Answer 1

@swim6963 Do you know ?

Answer 2

I know the rule

Answer 3

what? you actually wanna ask?

Answer 4

Did you see the attachment ?

Answer 5

I 1= 1/4 A
I 2 = 1/3 A
I 3= 1/2 A
I think so this should be the answer?

Answer 6

Please show work

Answer 7

I_1 =2/13
I_2= 7/13
I_3= 9/13
these are the answers

Answer 8

StarAngel: Do you know how to do the loop equations? If so, what do you get?

Answer 9

Applying KVL to the upper loop
\[-E1-I1\times R1+I2 \times R2+E2=0\]
Can you apply KVL for the bottom loop?

Answer 10

-E2-I2xR2-I3xR3-E3=0

Answer 11

Is that right ?

Answer 12

The last two would be positive, when we move against the direction of current across a resistor potential increases, and from -ve to +ve terminal of a battery, the potential increases

Answer 13

-E2-I2xR2-I3xR3+E3=0

Answer 14

-E2-I2xR2+I3xR3+E3=0

Answer 15

I'll explain you how this works:)

Answer 16

But along the direction its negative right?

Answer 17

You move along the direction in resistor R2 so -I2R2
but when we reach the lowermost branch, we move in opposite direction to the flow of current so =I3R3

Answer 18

In the lowermost branch we are moving along the flow of current isn't it?

Answer 19

No we move against it, let me show you with a diagram. Wait for 2 minutes