Here we go again, but this is cutting area horizontally. Find the area bounded by y^2=x, y-4=x, y=-2, and y=1. It doesn't end up working if you just manipulate until in terms of x, we're supposed to use the integral, but with dy. Anyone want to help?

Question

anonymous · Answer

http://www.wolframalpha.com/input/?i=area+y^2%3Dx%2C+y-4%3Dx%2C+y%3D-2%2C+y%3D1+ Here's what it looks like, but remember the width of the 'rectangles' is going to be dy.

anonymous · Answer

Need some help setting up the correct integrals.

anonymous · Answer

i am wondering if we can make life easy and swap x and y?

anonymous · Answer

http://www.wolframalpha.com/input/?i=area+x^2%3Dy%2C+x-4%3Dy%2Cx%3D-2%2C+x%3D1+

anonymous · Answer

I did try that! But I'm afraid that it might not work.

anonymous · Answer

Huh! maybe it does.

hoblos · Answer

$$\int\limits_{-2}^{1}(y ^{2}-(y-4))dy$$

anonymous · Answer

although maybe it doesn't really make any difference. going to integrat from -2 to 1 the bigger minus the smaller

anonymous · Answer

in this case the right minus the left

anonymous · Answer

Is it that simple? Wow >< Thanks guys.

anonymous · Answer

what hoblos wrote