Question

Please help, am i anywhere close with ps1?
count = 0
n = 1
while (count<=1000)
if n<=2:
n+1
count+1
while n>2:
if n/2:
break
if n%>n:
else:
count+1
print n

Answer 1

your indentation is messed up. pls use a code pasting site: dpaste.com, pastebin,com, codepad.org, ideone.com

Answer 2

totalNumberOfPrimeNumbers=2 #exclude prime number 1 & 3 from the list
n = 3
while totalNumberOfPrimeNumbers != 1000:
n += 2 #next odd integer to test if it's prime number
prime = True #assume it is a prime number
for i in range(3, n, 2): #check for only odd number as divisor
if (n % i) == 0:
prime = False #if prime number test fails, change boolean to False
break #no reason to continue testing
if (prime == True):
totalNumberOfPrimeNumbers += 1
print ('1000th Prime Number is {0}.'.format(n))

Answer 3

@bwCA
http://codepad.org/nlB6CSYa
hope this links it

Answer 4

@ paul30lee Thanks for posting this, but im not sure how the part where you "check for only odd number as divisor" works. I've been trying to use it and see how it works but I'm lost there. This is what i had but I couldn't get it to exclude some non primes. http://codepad.org/Sntd9hpw

Answer 5

jswtella - at line ten you cannot combine the % operator and the < operator.

you need to keep track of three things that are changing through a range of values -
count (the number of primes you have found),
n (the number you are testing) and
div (? - the number you are testing n with)

one way to do this is to have two loops:
oan outer loop that 'generates' and tests numbers to see if they are prime
an inner loop that 'generates' divisors to test n with

Answer 6

@ ks11 I was trying to put a #n is not divisible by anything less than n# in there somewhere but wasn't sure if that was possible or would actaully calculate accuratley.Thanks for having a look.
following bwCA's comments i will have to have a little re-think, i don't think i'm a million miles away!

Answer 7

you might want to consider using a while loop to 'keep track of' count (like you are doing) and generating new n's
then use a for loop with the range function for generating divisors
http://docs.python.org/tutorial/controlflow.html#for-statements

http://codepad.org/n2s0a7Kh