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Mathematics 17 Online
OpenStudy (anonymous):

One more proof question. malevolence19 if you could be so kind.

OpenStudy (anonymous):

OpenStudy (anonymous):

any thoughts?

OpenStudy (anonymous):

This one is a bit tougher haha

OpenStudy (anonymous):

yea its a fun class let me tell you

OpenStudy (anonymous):

I honestly don't know too much about sums of subsequences being convergent being related to absolute convergence of a series :/

OpenStudy (anonymous):

Lets think about it outloud

OpenStudy (anonymous):

Im wondering if i have to prove if i prove that bn is a cauchy sequence

OpenStudy (anonymous):

For b_n to be a subsequence of a_n then it must have the property that: \[b_k=\left\{ a_{n_k}| n_1 < n_2 < ... < n_k \in \mathbb{Z}^+\right\}\]

OpenStudy (anonymous):

Maybe I'm going too basic D:

OpenStudy (anonymous):

Im not sure. He posted this friday and we have a week to get it done so there is a possibility he hasnt covered it in class yet

OpenStudy (anonymous):

Do you know abel's test?

OpenStudy (kinggeorge):

Could you say that \(a_n\) is a subsequence of itself? Thus it's convergent. You still need to show absolute convergence, but this might be a good first step if it works.

OpenStudy (anonymous):

I mean we did just talk about rearrangement of series

OpenStudy (kinggeorge):

Absolute convergence would follow from the fact that \[\sum_{n=1}^{\infty} a_n\]converges. Since it converges at infinity, it's absolutely convergent.

OpenStudy (kinggeorge):

Just found this, it might help. http://www.physicsforums.com/showthread.php?t=209040

OpenStudy (anonymous):

it does. thanks

OpenStudy (kinggeorge):

you're welcome

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