Question

amplitude of oscillations

Answer 1

Use the property:
\[\sin(Bt \pm C)=\sin(Bt)\cos(C) \pm \sin(C)\cos(Bt)\]

Answer 2

someone explained part A to me, i need to learn how to do b and c about amplitude and fequency

Answer 3

actually, just the frequency. amplitude is simple

Answer 4

Because both waveforms have the same period, the sum of the waveforms will have the same period. Frequency= (w)/2pi, with w being the coefficient of t in both equations. If they didn't have similar w's then the least common multiple of the w's would have been the final w. In this case, we don't have to worry: Thus, the answer is 3/2pi, or 2)

Answer 5

For amplitude, it is the square root of the sum of the squares of amplitudes for both waves.

Answer 6

since you are adding a sine function to a cosine function, they are perpendicular to each other on a complex plane. Thus, the magnitude of the resultant wave function is found through Pythagorean theorem, which produces the aforementioned.

Answer 7

the amplitude would be sqrt10/2

Answer 8

now to find the frequency, what is the equation?

Answer 9

Yes. To find the frequency, you find the period. The frequency is just the inverse of the period. Since both waves here have the same period, the resultant sum of the waves will have the same period. Period: 2pi/3. So the frequency is.....

Answer 10

1/((2pi)/3)= 3/2pi! thanks