Question

f(x)=1/4(x+1)^2+6
find vetex,line of symmetry,max/min of f(x), value of f(-1)=6 the max or min? having a lot of trouble with this because of the 1/4

Answer 1

vertex is at x= -1, y=6

Answer 2

line of symm is x=-1

Answer 3

min is at vertex (f(x)=6)

Answer 4

value at f(-1)=6 is min

Answer 5

... get all this from a=1/4, b=1/2, c=25/4, after expanding the (x+1)^2 and simplifying.

Answer 6

so 6 is the max?

Answer 7

No, a min. The min value of the function is 6, meaning f(x)=6, and it occurs at x=-1.