Question

A negative charge of 2 x 10 ^ -8 c experiences a force of .060 N to the right in an electric field. What are the field magnitude and direction?

Answer 1

The vector Force F is equal to the product of the vector Electric field E and the scalar charge q,
\[ F = Eq \]

Now solve for E and notice it always in the direction of the force F if q is positive and the opposite direction of q is negative.

Answer 2

So then .06/(2x10^-8) = 3x10^6 to the left since q is negative?

Answer 3

Yes