what's the method for completing the square of something like : x^4 + 1/(16x^4) + 1/2

Question

what's the method for completing the square of something like :  x^4 + 1/(16x^4) + 1/2

anonymous · Answer

The quadratic formula works for everything, so if you can't figure it out, try using this.  
$$x=-b \pm \sqrt{b ^{2}-4ac}$$
everything on the other side of he x divided by 2a, i just couldn't figure out the way to show it on the equations thing.

anonymous · Answer

for my question can you tell me what the values for a b and c are?

anonymous · Answer

Did you write the equation correctly?

Did you mean $$x ^{4} +1/6x ^{2} +1/2$$

Either way you are going to have to let another variable equal  $$x ^{2}$$
So let $$k=x ^{2}$$

Note that $$(x ^{2})^{2}=x ^{4}$$

In the equation I wrote you would have  

$$k ^{2}+1/16k+1/2$$

Solve for k using the quadratic equation, and then solve for x by substituting k back into to where we let $$k=x ^{2}$$