It appears from the name of the HL Theorem that you actually need to know only two parts of a triangle in order to prove two triangles congruent. Is this the case? A. Yes, you only need to know the hypotenuse and a leg of a triangle. B. No, you actually need to know two sides and an angle, because the triangle must be a right triangle. C. No, you actually need to know three sides of the triangle. D. No, you actually need to know two angles and a side.
B. No, you actually need to know two sides and an angle, because the triangle must be a right triangle.
Choice A. implies that you know three parts of the triangle, leg, hypotenuse, and 90 degree angle. Other words one angle is right angle. I don't really understand the point of this question and its answers???
I said b because the question did not specify a right triangle. "you actually need to know only two parts of a triangle in order to prove two triangles congruent." It is not true that you need to know only two parts of a triangle in order to prove two triangles congruent.
Ah yes Directrix, B. would be the answer.
Would knowing an angle and the opposite side was equal in two triangles.....would they be congruent?
Choice D. Implies you know three angles, if two angles of a pair of triangles are equal, well the third angle would also be equal......again this question and answers is confusing.
Would knowing an angle and the opposite side was equal in two triangles.....would they be congruent? No.
I didn't think so.
Well since HL restricts it to right triangles it is making it more reasonable.
HL is the only time what would be known as SSA postulate for proving triangles works. Apart from right triangles, SSA, two sides and the non-included angle leads to the Ambiguous case in Trig.
I need to review trig, right after I review logs.
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