Question

suppose g(s)=(s^2)+3s+1. find a value c in the interval [0,5] such that g'(c) equals the average rate of change of g(s) on the interval [0,5].

Answer 1

im getting -3/2 or -1.5

Answer 2

What is the average rate of change of g on that interval?

Answer 3

41/5

Answer 4

No

Answer 5

(g(5) - g(0))/(5-0) = ( 41 - 1 ) / 5 = 8

Answer 6

its plus 1

Answer 7

Yes, and g(0) = 1.

Now, what's the derivative, g'(s)? And the solution of g'(s) = 8?

Answer 8

o nvm

Answer 9

2s+3

Answer 10

@JamesJ

Answer 11

Now you want a value of s such that
g'(s) = 8
i.e.,
2s + 3 = 8

Answer 12

its 2.5. thanks.

Answer 13

yes