two horses on opposite sides of a narrow stream are pulling a barge along the stream. Each horse pulls with a force of 720N. The ropes from the horses to a common point on the front of the barge from an angle of 60 degrees with each other. What is the resultant force exerted by the two horses?
Resolve the forces into two directions. One being the direction of the stream, call that the x-direction; and the other being perpendicular to it, the y-direction. Can you draw a diagram of the situation?
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Right, so each rope makes an angle of 30 degrees to the x-direction. Hence if T is the tension and force in each rope, the component of that force of one rope in the x-direction is \[ F_x = T \cos(30) = (720).(\sqrt{3}/2) = ... \]
Now see how to finish this problem?
ya, is it 1.225?
No. What is the x component of the force from one of the horses?
uhm I don't really understand
oh is it 881.816?
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