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OpenStudy (anonymous):
You need a common denominator. What would it be?
OpenStudy (anonymous):
9 right?
OpenStudy (anonymous):
No, what is similar in the denominators... 3x... x ?
OpenStudy (anonymous):
x divides into 3x 3 times
OpenStudy (anonymous):
The first fraction lacks an "X" and the 2nd fraction lacks a "3X"
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OpenStudy (anonymous):
on the dominator.
OpenStudy (anonymous):
So your Common Denominator would be (3x)(x)
OpenStudy (anonymous):
Oh alright gotcha
OpenStudy (anonymous):
You would times 2 by "x" and 3x by "x"... since you want to make the 1st equation have the same denominator.
OpenStudy (anonymous):
so it would be 2x/(3x)(x) - (3x)/(3x)(x)
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OpenStudy (anonymous):
2x-3x = -1x
OpenStudy (anonymous):
the answer is -1x/(3x)(x)
OpenStudy (anonymous):
so basically u would multiply the right side by the denominator of the left side and multiply the left side by the denominator of the right side?
OpenStudy (anonymous):
kind of
OpenStudy (anonymous):
Yes, whatever the other doesn't have on the (bottom) denominator.. you have to TIMES it by the Numerator and the Denominator.. Whatever you do to the denominator you have to do to the numerator.
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OpenStudy (anonymous):
seems simple thanks bro u explained very well
OpenStudy (anonymous):
It gets harder.. haha
OpenStudy (anonymous):
and u know how 3x^2 doesnt go into 2x do u just write it as 2x-3x cause 3x doesnt go into 2x?