Question

With these dimensions: Dimensions. The pool will hold 2,000 ft3 of water, be 8 inches deep(height), have a width of 5 feet and a length of 50 feet.
What is the lateral area? Be in mind this is for a pool and the top side is missing.

Answer 1

You will only need to compute the area of the 4 sides, as lateral area excludes the area of the base.

Answer 2

Convert the 8 inch to dimension to feet: 8/12=2/3 ft.
The width sides would be 2/3 ft. X 5 ft, Area A=2/3 X 5 since there are two sides the area of both sides: A= 2(2/3)(5)

Compute the area of the length sides: A=(2/3)(50), again there are 2 long sides so the area for both long sides would be: A=(2)(2/3)(50)
total area would be the sum of the 4 sides: A(total)=100(2/3) + 10(2/3):

200 20 220
---- + ----- = ----- = 73 1/3 Sq. Ft.
3 3 3

Answer 3

If decimal answer is desired then: 73.33333333333333333333333333 Sq ft.

Answer 4

Just kidding, 73.33 ought to get it.

Answer 5

Thanks! haha

Answer 6

You're welcome and good luck with your studies.