Question

Does anybody know how to integrate: ?
0 to 50 ʃ 1- (t/100)^1.5 dt

Answer 1

\[\int (1-(\frac{t}{100})^{1.5})dt=t-0.0004t^{2.5}\] evaluate across limits.

Answer 2

can u somehow show me the steps please..will be grateful

Answer 3

\[\int (1-(\frac{t}{100})^{1.5})dt = \int (1-0.001t^{1.5})dt=\int 1 dt-\int 0.001t^{1.5}dt\]
\[=\int 1 dt - 0.001\int t^{1.5}dt=t-0.0004t^{2.5}\]

Answer 4

Thanks