Now that you have the amount of fluorine gas in moles, you can start the stoichiometry problem.

0.895 mol F2 × (2 mol NaCL/1 mol F2) × (58.44 g NaCl/1 mol NaCl) = 105 g NaCl

Why didn't they convert the flourine

Question

Now that you have the amount of fluorine gas in moles, you can start the stoichiometry problem.

0.895 mol F2 × (2 mol NaCL/1 mol F2) × (58.44 g NaCl/1 mol NaCl) = 105 g NaCl

Why didn't they convert the flourine

aravindg · Answer

hmm.i didnt get ur qn .can u be clear

anonymous · Answer

when the y started the stoichiometry problem why did they use "(2 mol NaCL/1 mol F2)" that first?