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IIT study group 8 Online
OpenStudy (anonymous):

Now that you have the amount of fluorine gas in moles, you can start the stoichiometry problem. 0.895 mol F2 × (2 mol NaCL/1 mol F2) × (58.44 g NaCl/1 mol NaCl) = 105 g NaCl Why didn't they convert the flourine

OpenStudy (aravindg):

hmm.i didnt get ur qn .can u be clear

OpenStudy (anonymous):

when the y started the stoichiometry problem why did they use "(2 mol NaCL/1 mol F2)" that first?

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