Ask your own question, for FREE!
Mathematics 7 Online
OpenStudy (anonymous):

lim (x -> infinity) (11+8x)/(x^3+7x)= 0 why?

OpenStudy (anonymous):

because the degree of the denominator is larger than the degree of the numerator try it with x = 10^6 and you will see why this makes it true

OpenStudy (anonymous):

so whenever the degree of the denominator is greater than the numerator, the answer is 0?

OpenStudy (anonymous):

Because as x tends to infinity, the numerator becomes insignificant in comparison to the denominator, since the highest degree of the numerator in terms of x is 1, whilst the numerator, 3.

OpenStudy (anonymous):

if by "whenever" you mean as x goes to infinity, the answer is yes

OpenStudy (anonymous):

oh! so because the numerator is insignificant compared to the denominator, anything divided by infinity equals zero

OpenStudy (anonymous):

well, the limit i mean

OpenStudy (anonymous):

so how would it change if it was going to negative infinity?

OpenStudy (anonymous):

still zero

OpenStudy (anonymous):

-.000000001 vs .000000001 still close to zero

OpenStudy (anonymous):

thanks

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!