lim (x -> infinity) (11+8x)/(x^3+7x)= 0 why?
because the degree of the denominator is larger than the degree of the numerator try it with x = 10^6 and you will see why this makes it true
so whenever the degree of the denominator is greater than the numerator, the answer is 0?
Because as x tends to infinity, the numerator becomes insignificant in comparison to the denominator, since the highest degree of the numerator in terms of x is 1, whilst the numerator, 3.
if by "whenever" you mean as x goes to infinity, the answer is yes
oh! so because the numerator is insignificant compared to the denominator, anything divided by infinity equals zero
well, the limit i mean
so how would it change if it was going to negative infinity?
still zero
-.000000001 vs .000000001 still close to zero
thanks
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