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OpenStudy (anonymous):
How would I find the derivative of this: Find f(x) = x^2 + 3 sin x
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OpenStudy (anonymous):
Use the power rule on x^2. 2x^(2-1) = 2x. Then let D3sinx be (3)Dsinx. The derivative of sinx is always cosx. So you have 3cosx. Therefore, 2x + 3cosx! This site should help you with the derivatives of sin, cos, and such: http://www.sosmath.com/calculus/diff/der03/der03.html
OpenStudy (anonymous):
Does that help?
OpenStudy (anonymous):
a lot thanks!
OpenStudy (anonymous):
You're welcome!
OpenStudy (anonymous):
2x+3cosx bcoz x^n gives us nx^(n-1)and3cosx i have solved with help of product rule
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