Question

If f(x)=x^3+4x+6, find (f−1)′(6)

Answer 1

its actaully( f^-1)'(6)

Answer 2

i meant to correct that. sorry

Answer 3

\[(f^{-1})'(6)=\frac{1}{f'(f^{-1}(6))}=\frac{1}{f'(0)} \text{ since } f(0)=6 => f^{-1}(6)=0\]

Answer 4

0 doesnt work

Answer 5

Can i have some help?

Answer 6

\[f'(x)=3x^2+4 =>f'(0)=3(0)^2+4=4 => (f^{-1})'(6)=\frac{1}{4}\]

Answer 7

Oh, he meant inverse. I'm sorry. I'll delete my answer.

Answer 8

1/4 works thanks myinaya

Answer 9

I know it works lol

Answer 10

Oh you thought I was saying the answer is 0?
Do you understand the steps?