http://screensnapr.com/v/HuXbW3.png Solve for angle 1 & 2, and x & y.
@angela210793
Theres no way this is geometry, honestly, the most we used SohCahToa for in geometry honors was just knowing trig ratios.
I'm sorry...I don't think I can solve this....(I'm too tired...can't think) :S
This is a load of BS. Im seriously complaining to my girlfriends teacher.
hahaha lol xD
maybe @JamesJ can help
Someone in AP calculus should be able to do geometry, but no! This is just madness!
I assume the ST and QR are parallel, as are the the opposite pair: TQ and SR.
You need to write down four linear equations to be able to solve for the four variables: #1, #2, x and y. It's it not so bad; just takes some working through. For example consider the angles between TQ and SR on the left. They must sum to 180 degrees. Hence (3x + 2) + #2 + #1 + 53 = 180 Another equation comes from the triangle on the left. The angle opposite x+3 is also x+3 hence #1 + #2 + (x+3) = 180 and so on.
Check my new problem James, I left out a y somewhere, perhaps thats where its messing everyone up.
Actually the first thing to do is to solve for x. Call the center point C. Then the angle TCQ is 180 - (x+3) = 179 - x. The angle TQC = QSR = 53. Hence the angles of the triangle TCQ must add to 180 and thus (179 - x) + 53 + (3x + 2) = 180 From this you can solve for x. And then you are on your way.
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