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how do you find the inverse of f(x) = 2^x
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log_2 (x)
y=2^x
ln(y)=xln2 x=ln(y)/ln(2) \[f^{-1}(x)=\ln(x)/\ln(2)\]
The inverse function for 2^x is log base 2 of x (log_2 (x)).
... which can be written in terms of other logarithms, like ln, by using log_2 (x) = ln(x) / ln(2), as in what .Sam. wrote, for example. But the simplest answer is log_2 (x).
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