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f(x) = 1/(sqrt[x+2]); find f'(a) ?
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stuck at -(sqrt[x+2])/(x+2)
(1)/(~(x+2)) Add 0 to 1 to get 1. (d)/(dx) x+2=1 Multiply the rational expressions to get -(1)/(2(x+2)^((3)/(2))). (d)/(dx) (1)/((x+2)^((1)/(2)))=-(1)/(2(x+2)^((3)/(2))) The derivative of (1)/((~(x+2))) is -(1)/(2(x+2)^((3)/(2))). -(1)/(2(x+2)^((3)/(2)))
what does ~ mean
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