ln(uv^3)^10=A ln u+B ln v what are A and B?
\[\ln(ab)=\ln(a)+\ln(b)\] use this first
on \[ln(uv^3)\]
\[\ln(u)+\ln(v^3) \text{ like this}\]
now use \[\ln(x^r)=r\ln(x)\] and you are basically done
i dont get how i am suppose to enter these variables into my calc
\[\ln(u)+3 \ln(v)\] I just used that rule I put
\[1 \ln(u)+3 \ln(v)\]
So now it is easy for you to determine which is A and which is B
so what is A? and what is B?
A ln(u) + B ln(v) 1 ln(u) + 3 ln(v) Do you see what A and B is?
1 and 3?
Oh I didn't see that ^10 at first
\[\ln((uv^3)^{10})\] is that right?
yea
\[10 \ln(u v^3)=10 (\ln(u)+\ln(v^3))=10 \ln(u)+10 \ln(v^3)=10 \ln(u)+10(3) \ln(v)\]
So A is? and B is?
10 and 30 thanks for the help. i have 2 more similar but somewhat different
Use the laws of logarithm to rewrite the expression log (x^14 y^12/ z^13) in a form with no logarithm of a product, quotient, or power. After rewriting we have log (x^14 y^12/ z^13)= A log(x) + B log(y) + C log(z). what are A, B, and C? i got a and b, just need c
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