Evaluate the limit:
lim h - 0
(((5+h)^2 + 1)/(5+h) - 26/5 ) / h

Question

Evaluate the limit:
lim h -> 0
(((5+h)^2 + 1)/(5+h) - 26/5 ) / h

anonymous · Answer

$$\lim_{h \rightarrow 0}  (((5+h)^{2} + 1 / (5+h) ) - 26/5) / h$$

hero · Answer

Simplify, as much as possible, then substitute h = 0 into the expression.

hero · Answer

You want to simplify until h can cancel in the denominator.

hero · Answer

Once you have done that, then you can substitute h = 0 and find the limit

hero · Answer

I wasn't trying to butt in merstj. You can continue posting your solution. Just giving general steps

anonymous · Answer

no limit,

anonymous · Answer

i know... I'm having trouble simplifying...

mertsj · Answer

$$\frac{25+10h+h^2+\frac{1}{5+h}-\frac{26}{5}}{h}$$

mertsj · Answer

The limit does not exist because as you approach from the left the limit is negative infinity and as you approach from the right the limit is positive infinity