Question

please help me. my teacher does not know how to teach.

Answer 1

if sin(v) = 1/2 what is cos(v) and what is tan (v)

Answer 2

that is the v symbol idk what its called

Answer 3

It's just v ;)

Answer 4

Draw a triangle.

OR

use identities:

sin^2(v) + cos^2(v) = 1

(1/2)^2 + cos^2(v) = 1
cos^2 (v) = 3/4

cos (v) = +- sqrt(3)/2

to get tan v, use the fact that sin v/cos v = tan v

Answer 5

either take this seriously or gett of my question

Answer 6

*get off

Answer 7

we never learned this. can u please just tell me

Answer 8

What should I tell you? I pretty much gave you the answer there

Answer 9

Horrible—telling you will not help you learn.

Answer 10

What exactly do you think he wasn't taking seriously? He explained exactly how to get your answer. Please be polite to users who are trying to help you.

Answer 11

sorry i didn't see the answer. can u help me with more. and shadow fiend i was talking to you. you can get off my question, thanks.

Answer 12

wait so what for tan?

Answer 13

\[\tan v ={\sin v \over \cos v}\]

\[\sin v = {1 \over 2}\]
\[\cos v = \pm {\sqrt3 \over 2}\]

Answer 14

what does tan v equal!

Answer 15

Do it yourself.

Answer 16

i don't get how?

Answer 17

I just told you it's sin v / cos v? read my instructions.

Answer 18

one third?

Answer 19

I DONT GET THIS. I SAID MY TEACHER NEVER TAUGHT US AND JUST THREW THIS SHEET AT US

Answer 20

I HATE MY LIFE

Answer 21

Hypothetical question:

if A = 1 and B = 2

What is: \[A \over B\]

Answer 22

I KNOW THE ANSWER IS 1/ SQRT 3 BUT I HAVE A BOX OF LIKE A BUNCH OF ANSWERS AND THAT IS NOT ONE OF THEM

Answer 23

Ok, there's one last step then :)

Answer 24

\(\frac{1}{\sqrt{3}}\) can be expressed a different way.

Answer 25

It's called “rationalizing” the denominator, and it involves taking square roots out of the denominator.

Answer 26

HOW PLEASE JUST TELL ME I AM LATE FOR WORK

Answer 27

Okay, now here's something you should learn:

If there's a square root in the denominator, then you must rationalize the denominator.

\[{1 \over \sqrt3} * { \sqrt 3 \over \sqrt 3} = {\sqrt 3 \over 3}\]

Answer 28

In this case, because there's a \(\sqrt{3}\) in the denominator, you can multiply the fraction by \(\frac{\sqrt{3}}{\sqrt{3}}\), which leaves you with \(\frac{\sqrt{3}}{3}}\).

Answer 29

Heh. What slaaibak said ^^ :)

Answer 30

thank u. can i come back in 3 hours and you guys help me more

Answer 31

I may or may not be here, but there will definitely be people here :)

Answer 32

plz take a look at my other question