Question

round 2...

Answer 1

-10.7

Answer 2

unfortunately... didn't work.

Answer 3

Can you try again?

Answer 4

i have no idea how you got that far in the first place...

Answer 5

\[\log_{9}u=2.5 \]
\[9^{2.5}=u\]
\[(3^2)^{2.5}=u\]
\[3^{7.5}=u\]

Answer 6

\[\log_{9}v=7.6 \]
\[9^{7.6}=v\]
\[(3^2)^{7.6}=v\]
\[3^{15.2}=v\]

Answer 7

\[\log_{9}\frac{u}{27v}=\log_{9}\frac{3^{7.5}}{3^3(3^{15.2})} =\log_{9}(3^{-10.7)}=x\]

Answer 8

\[9^x=3^{-10.7}\]

Answer 9

\[(3^{2})^{x}=3^{-10.7}\]

Answer 10

\[3^{2x}=3^{-10.7}\]

Answer 11

\[2x=-10.7\]
\[x=-5.35\]

Answer 12

Can you try that or do you get another chance?

Answer 13

i have unlimited chances haha, still didn't work out though

Answer 14

Try -6.6. I found a mistake.

Answer 15

well, nice job. you found your mistake. I'd would attempt some of these myself but my professor gave us hw before break without teaching us...

Answer 16

So it worked?

Answer 17

yes sir, you seem surprised? haha