Question

How would you solve this: log2 (a^2 -6a)= log2 (10+3a)?

Answer 1

\[\log_2{(a^2-6a)}=\log_2{(10+3a)} \]

Answer 2

a^2 -6a = 10+3a

Answer 3

a^2 -6 = 10 + 3a
a^2 -9a -10 = 0
=> a = 10 ( discard a = -1 not belongs to domain of log)

Answer 4

Since the logs and bases are the same, drop them and just solve the two sided equation.

Answer 5

@Chlorophyll how did you get a=10 from a^2 -9a -10=0?

Answer 6

factor it

Answer 7

You just got answered from lisapeajac!

Answer 8

Oh, see, I'm so used to not skipping steps and showing my work that I got confused when you didn't. But I get it.

Answer 9

That's how you learn :)

Answer 10

Yep. CPR. Get Comfortable with Confusion (C), Persistent in Problemsolving (P), and Reliable in ...Something I forgot... (R). CPR.