Mathematics
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OpenStudy (anonymous):
h(t)=-16t^2+781......determine the average velocity on the interval (2,4)
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OpenStudy (anonymous):
I believe the average velocity is equal to the first derivative.
OpenStudy (anonymous):
how'd you come to that conclusion?
OpenStudy (anonymous):
From studying calculus- it is on p. 171 of my calc text. Plus, I'm a math teacher.
OpenStudy (anonymous):
oh niiice thank you
OpenStudy (anonymous):
I got 32x....is that correct?
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OpenStudy (anonymous):
yes sir!!!!
OpenStudy (anonymous):
yesss!!!! thank you
OpenStudy (anonymous):
thank you!
OpenStudy (anonymous):
now i have to determine the instaneous velocity at times t=2 and t=4
OpenStudy (anonymous):
so plug that into 32x for x. Your x is your time.
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OpenStudy (anonymous):
for both times?
OpenStudy (anonymous):
yes. One answer per time since the velocity is changing with respect to time
OpenStudy (anonymous):
i got 1293 is that correct?
OpenStudy (anonymous):
For t equals 2, it should be 32 times2 = 64, and for t=4, it should be 32 times 4 = 128
OpenStudy (anonymous):
but what about that 781?
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OpenStudy (anonymous):
The derivative of a constant is zero and the velocity is just 32t
OpenStudy (anonymous):
oh okay I see
OpenStudy (anonymous):
yay!