Question

Can someone please tell me if I am doing this correct so far please. Integration: I will type it below

Answer 1

sure go ahead

Answer 2

\[\int\limits (x^2+1 )e^x dx\]

let u=x^2 +1 dv = e^x dx
du = 2x dx v=e^x dx

then following the formula I put

\[\int\limits (x^2+1)e^x = x^2(e^x) - \int\limits (e^x)(2x dx)\]

Answer 3

make your live easy and multiply out first

Answer 4

\[\int x^2e^xdx+\int e^xdx\] second integral is just
\[e^x\] and parts for the first one

Answer 5

Also, if you do decide to use \(u=x^2+1\), then the term in front should be \[(x^2+1)(e^x)\]not \[x^2(e^x)\]

Answer 6

always when solving integrals, it becomes easy when you expand the factorized stuff

Answer 7

actuall you will need parts twice

Answer 8

yeah I just wanted to make sure I had the first part correct. for my second part I made u=x du=dx dv = e^x and v=e^x

Answer 9

how do I expand it Shana?

Answer 10

take 2 out of the integral
your u n v are correct. go ahead with that. wait i ll attach a drawing..