Iron has a mass of 7.87 g per cubic centimeter of volume, and the mass of an iron atom is 9.27 × 10^-26 kg. If you simplify and treat each atom as a cube, (a) what is the average volume (in cubic meters) required for each iron atom and (b) what is the distance (in meters) between the centers of adjacent atoms?

is (a)1.18*10^-29m^3 ?

Question

Iron has a mass of 7.87 g per cubic centimeter of volume, and the mass of an iron atom is 9.27 × 10^-26 kg. If you simplify and treat each atom as a cube, (a) what is the average volume (in cubic meters) required for each iron atom and (b) what is the distance (in meters) between the centers of adjacent atoms?

is (a)1.18*10^-29m^3 ?

anonymous · Answer

and in (b) do you just use cube root of (a)?

anonymous · Answer

i got the density at 7.87x10^3 kg/m^3, so the volume of 1 atom would be 1.18x10^-29kg for a

anonymous · Answer

so (b) is 2.28*10^-08

anonymous · Answer

1.18x10^-29m^3 rather

anonymous · Answer

i would think you'd take the cube root for part b, center to center is same as edge to edge

anonymous · Answer

for part b i got 2.28x10^-10m

anonymous · Answer

hmmm mine is 2.28*10^-08m when i put cuberoot this 1.18x10^-29m^3

anonymous · Answer

you able to tell why?

anonymous · Answer

you put it all in parentheses in calculator?
(1.18x10^-29)^(1/3)

anonymous · Answer

well i used the $$\sqrt[3]{1.18x10^-29m^3}$$

anonymous · Answer

your answer is right for cm, but not for m

anonymous · Answer

if you cube 2.28x10^-8 you get 1.18x10^-23

anonymous · Answer

yes thats right

anonymous · Answer

but they want the answer in m, not cm

anonymous · Answer

but all the measurements were in metres when we were doing the calculation???

anonymous · Answer

$$\sqrt[3]{1.18*10^{-29}} \approx 2.28*10^{-10}$$

anonymous · Answer

lol ok. i believe you

anonymous · Answer

ok :)

anonymous · Answer

but how come if you go cuberoot 1000 it equals 10?

anonymous · Answer

it doesn't change to cm

anonymous · Answer

it is 10m

anonymous · Answer

??

anonymous · Answer

right

anonymous · Answer

from 1000m

anonymous · Answer

yep

anonymous · Answer

http://www.wolframalpha.com/input/?i=%281.18*10%5E-29%29%5E%281%2F3%29

anonymous · Answer

maybe you enter it in calculator wrong?

anonymous · Answer

lol nah just missed the logic i guess

anonymous · Answer

you found the density in kg/m^3 right?, not g/m^3?

anonymous · Answer

yep

anonymous · Answer

(1.18x10^-29m^3)^(1/3)

anonymous · Answer

in the calculator

anonymous · Answer

yes, and you don't get what i got?

anonymous · Answer

nope...i have an old casio calculator

anonymous · Answer

must be the qay it is entered in...

anonymous · Answer

yes very strange

anonymous · Answer

ok i need sleep LOL i entered in the (1.18x10^-23)^(1/3)

anonymous · Answer

omg

anonymous · Answer

lol

anonymous · Answer

at least your calculator is in working order

anonymous · Answer

haha yep. the other calculator is busted though