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A chair of mass 16.4 kg is sitting on the horizontal floor; the floor is not frictionless. You push on the chair with a force of 69.8 N that is directed at an angle of 21.5 degrees below the horizontal and the chair slides along the floor. Calculate the normal force that the floor exerts on the chair. Give your answer in Newtons to the first decimal place.
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|dw:1331110516219:dw|
the normal reaction would be: \[mg+F \sin \theta\]
is it clear?
Got it, thanks again!
no problem
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