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Mathematics 13 Online
OpenStudy (anonymous):

\[Let ~~ f(a)={cosA \over 1 +sinA}+{1+sinA \over cosA}\]\[(a) ~Prove ~that ~~f(A)=2secA\]

OpenStudy (anonymous):

multiply the first fraction by (1-sinA) both num and denom one cos A gets cancelled then u may have (1+sinA+1-sinA)/cosA = 2secA

OpenStudy (anonymous):

Hm. Ok. that makes sense.

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