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OpenStudy (anonymous):
A=1 degrees
OpenStudy (anonymous):
for 2secA
OpenStudy (anonymous):
search on the net?
OpenStudy (anonymous):
It doesn't work.
OpenStudy (anonymous):
Is this the full question?
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OpenStudy (anonymous):
No.
4=2secA
(which is 1 degrees ~ because it's asking for degrees).
Then you need to find the solutions in the intervals that I gave.
OpenStudy (anonymous):
ans is 60 degrees
OpenStudy (anonymous):
Why?
OpenStudy (anonymous):
4 = 2sec(A)
divide both sides by 2
2 = sec(A)
sec(A) = [1/cos(A)]
For this reason multioly both sides by cos(A), OR u can say cross multiply
2cos(A) = 1
Divide both sides by 2
cos(A) = 1/2
A = \[\cos^{-1} (1/2)\]
So A = 60
OpenStudy (anonymous):
Hm Ok.
But wy first switch the 2 to 1/2 because adding the cos? Which would give 1...
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OpenStudy (anonymous):
Which step are u talking about
OpenStudy (anonymous):
Um, never mind. I get it. :)
OpenStudy (anonymous):
There's another answer though. The other is 300.
OpenStudy (anonymous):
Cool, good luck
OpenStudy (anonymous):
thanks
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OpenStudy (anonymous):
Your welcome, how is your calculus coming along
OpenStudy (anonymous):
cos function repeats after 2(pi) degrees hence general solutions for cosine functions are
\[2n \pi -\alpha\]
where alpha is the angle
hence put n=1
hence you get your other answer as 300 degrees