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Mathematics 8 Online
OpenStudy (anonymous):

i need help simplifying

OpenStudy (anonymous):

OpenStudy (anonymous):

Do you know the answer? I think I have it, but I'm not sure if the calculations are completely correct.

OpenStudy (anonymous):

no i dont, i have simplified the 10x^4 to equal 2x^2 and the 15x^2 to equal 3. thats as far as i got

OpenStudy (anonymous):

I have \[2x^3+3x^2 \over 2(4x-3)\]

OpenStudy (anonymous):

that is one of the options my question has. can you explain how you got that answer?

OpenStudy (anonymous):

Yes. Let me write it down for you.

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

\[{6x+9 \over 15x^2} \div {16x-12 \over 10x^4}\] you can cancel the denominators as far as possible, since cross multiplying will make it so that you can. ----->\[{6x+9\over 3} \div {16x-12 \over 2x^2}\]

OpenStudy (anonymous):

Do you get this so far?

OpenStudy (anonymous):

After this, you can now factor the 6x-9 so that you can cancel out the 3. \[{3(2x+3) \over 3} \div {16x-12 \over 2x^2}\]

OpenStudy (anonymous):

\[(2x+3) \div {4(4x+3) \over 2x^2}\]

OpenStudy (anonymous):

Now, you can cancel out the 2. \[(2x+3) \div {2(4x+3) \over x^2}\]

OpenStudy (anonymous):

Can you carry on from here, or should I show you the last steps?

OpenStudy (anonymous):

dont you have to flip the 16x-12/2x^2 so that the 2x^2 is the numerator?

OpenStudy (anonymous):

That's if you want to multiply straight instead of doing it at the end... You'd have to change the divide sign to the times sign. eg -----> \[(2x+3) \times {x^2 \over 2(4x+3)}\]

OpenStudy (anonymous):

So, yes. You could do it like this, and now times the fractions. :) It would give you the same answer.

OpenStudy (anonymous):

would it be easier to simplify everything then multiply?

OpenStudy (anonymous):

For me, yes. And it can take less time, but if you're not used to it, then it might be easier to first multiply.

OpenStudy (anonymous):

So, do you understand it now?

OpenStudy (anonymous):

yeah a little more. can you show me how you got the final answer?

OpenStudy (anonymous):

Sure.

OpenStudy (anonymous):

Now, that it's flipped, you can easily just multiply the fractions -----> \[2x^2(x+3) \over 2(4x-3)\]------->\[2x^3 +3x^2 \over 2(4x-3)\]----> Which is the final answer.

OpenStudy (anonymous):

thank you!

OpenStudy (anonymous):

Um hold on. I made a little mistake in explaning.

OpenStudy (anonymous):

It should be \[x^2 \]not \[2x^2\] and it should be (2x+3) not (x+3)

OpenStudy (anonymous):

I just made that mistake in the last part. The other steps were correct :)

OpenStudy (anonymous):

i like ur pic. @order

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