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Mathematics 20 Online
OpenStudy (anonymous):

How do I determine the area under this semicircle without using numerical approximation?

OpenStudy (anonymous):

OpenStudy (anonymous):

The area of a circle is A = pi * r^2 The radius is 3, and this is half of a circle The area is then 3^2 * pi / 2 = (9/2) * pi

OpenStudy (anonymous):

I think that might be considered numerical approximation.

OpenStudy (anonymous):

Radius = 3, so the area would be like 1/2(pi * r^2) where your r = 3. Since it's a multiple of pi, it's an exact answer, otherwise you could just do an integral of it.

OpenStudy (anonymous):

Take the integral of sqrt(9-x^2) = F(x) The area is then F(3) - F(-3)

OpenStudy (anonymous):

I think they don't want me to use integration on this.

OpenStudy (anonymous):

I believe my first solution avoids numerical approximation, whereas the second does not...

OpenStudy (anonymous):

I said semicircle because it looked like one. It's not stated that it is a semicircle, so I'm not sure it counts as one.

OpenStudy (anonymous):

This is a semicircle... y = sqrt(9-x^2) so y^2=9-x^2 x^2+y^2 = 9 The standard equation of a circle is x^2 + y^2 = r^2

OpenStudy (anonymous):

ohh....okay. Thanks!!

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