what is the equation of the tangent line and of the normal line at the curve y = x^4 + 2e^x at the point (0,2) ?
find the derivative and plug in the point (0,2) that will be the slope for the tangent line.
next since you have a point you can use point slope form to find the tangent line y-y1=m(x-x1) where m is the slope( I already told you have to figure that out) x1 and y1 is your point (0,2) = (x1,y1) plug them in
if you wish to simplify then isolate y
no but what's the difference between the tangent line and the normal one!!!!
my textbook says the tangent line equation is y = 2x + 2 and the normal is y = (-1/2)(x) + 2
I got y = 2x + 2 as the tangent line by following the steps I showed you for finding the tangent line
The normal line is defined as the line that is perpendicular to the tangent line at the point of tangency.
which makes sense because perpendicular lines have an inverse of slope where the slope of the tangent line is 2 so inverse of 2 is -1/2
Join our real-time social learning platform and learn together with your friends!