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Mathematics 19 Online
OpenStudy (ragingsquirrel):

Just double checking A square has a triangular hole in it. What is the area of the figure? 100 in2 92.5 in2 85 in2 70 in2

OpenStudy (ragingsquirrel):

hero (hero):

\[A_{total} = s^2 - \frac{bh}{2}\]

OpenStudy (ragingsquirrel):

It's 85 right?

OpenStudy (anonymous):

It might be the area of the square, less the area of the triangle. I think that is about\[10^{2}-3*5/2=92.5\]Approximately.

hero (hero):

By the way, @AnimalAin , that would be an exact value, not an approximate one.

OpenStudy (anonymous):

Measured distances are always approximate, no?

hero (hero):

We're computing, not measuring

OpenStudy (anonymous):

OK, I concede. LOL

OpenStudy (anonymous):

we only use approximation when taking data....when we collect data the tools we use have some degree of uncertainty.

OpenStudy (ragingsquirrel):

Can i just have the answer...

hero (hero):

@AnimalAin, if what you said were true, the formula would look like this: \[A_{total} \approx s^2 - \frac{bh}{2}\]

OpenStudy (anonymous):

Got me again!

OpenStudy (anonymous):

well what Hero is saying is find the area of the square then find the area of the triangle. Subtract the area of the triangle from the square.

OpenStudy (anonymous):

Check the fourth post in the thread.

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