Just double checking A square has a triangular hole in it. What is the area of the figure? 100 in2 92.5 in2 85 in2 70 in2
\[A_{total} = s^2 - \frac{bh}{2}\]
It's 85 right?
It might be the area of the square, less the area of the triangle. I think that is about\[10^{2}-3*5/2=92.5\]Approximately.
By the way, @AnimalAin , that would be an exact value, not an approximate one.
Measured distances are always approximate, no?
We're computing, not measuring
OK, I concede. LOL
we only use approximation when taking data....when we collect data the tools we use have some degree of uncertainty.
Can i just have the answer...
@AnimalAin, if what you said were true, the formula would look like this: \[A_{total} \approx s^2 - \frac{bh}{2}\]
Got me again!
well what Hero is saying is find the area of the square then find the area of the triangle. Subtract the area of the triangle from the square.
Check the fourth post in the thread.
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