Question

Calc III Help.
Find all the second partial derivatives.
z=2xe^y - 3ye^-x

Answer 1

all of them?

Answer 2

that sounds like alot

Answer 3

I have z(xx) = 3ye^-x
z(yy) = 2xe^y
and z(xy) = 2e^y + 3e^x

Answer 4

Zx = 2e^y +3ye^-x

Answer 5

Zy = 2xe^y -3e^-x

Answer 6

Yea that is what I have for both first partial derivatives.

Answer 7

Zxx = -3ye^-x

Zxy = 2e^y +3e^-x

Zyy = 2xe^y

Zyx = 2e^y +3e^-x

Answer 8

its just a matter of keeping your wits about you and letting your fingers do the mathing ...

Answer 9

Yea. Thank you for the help seems like I am just forgetting to bring down negatives from the exponents. Glad to know I am not completely lost.

Answer 10

yeah, you did fine; just focus on one thing at a time and when you know its right move to the next one ;)

Answer 11

Yea. Thank you again.