Question

What is 6 over x^3-64 minus 4 over x^2-16???

Answer 1

\[\frac{6}{x^2-64}=\frac{6}{(x-4)(x^2+4x+16)} \]
\[\frac{4}{x^2-16}=\frac{4}{(x-4)(x+4)}\] is a start

Answer 2

typo there, first line should be
\[\frac{6}{x^3-64}=\frac{6}{(x-4)(x^2+4x+16)}\]

Answer 3

so least common multiple of the denominators is
\[( x+4)(x-4)(x^2+4x+16)\]

Answer 4

How would i write it all out? And get the answer?

Answer 5

can u draw the question?

Answer 6

Yes hold on