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OpenStudy (anonymous):
For what values of a and b is the line 2x+y=b tangent to the parabola y = ax^2 when x = 2?
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myininaya (myininaya):
Have you found y'?
OpenStudy (anonymous):
of which ONE
myininaya (myininaya):
Find y' and put 2x+y=b into this form: y=mx+c to find m
Then set y'=m
OpenStudy (anonymous):
like y' = 2ax? that one? i start there?
myininaya (myininaya):
ok now set y'=the slope of the tangent line
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OpenStudy (anonymous):
uh you mean like 2x + y = b ==> y = -2x+b .. ?
myininaya (myininaya):
and also we want to know what a is when x=2
so we have
2a(2)=the slope of the tangent line
OpenStudy (anonymous):
oy
myininaya (myininaya):
y=-2x+b
so the slope of tangent line is -2 right?
myininaya (myininaya):
\[2a(2)=-2\]
solve for a! :)
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OpenStudy (anonymous):
ah
myininaya (myininaya):
\[a=-\frac{1}{2}\]
we also need to find b though!
myininaya (myininaya):
when x=2, what is f(2)?
myininaya (myininaya):
i will let you tell me
myininaya (myininaya):
f(x)=ax^2
we found a
what is f(2)?
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myininaya (myininaya):
The reason we need this is so we can know a point on the tangent line so we can solve for b
myininaya (myininaya):
2x+y=b
2(2)+f(2)=b
4+f(2)=b
so once you find f(2) you will be able to find b
myininaya (myininaya):
Right
We could say that with out the bad language part though please
myininaya (myininaya):
without*
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