integrate $${2 \over 3(sec x-1)}$$

Question

anonymous · Answer

If you could write out the steps, that'd be nice. I just keep getting the wrong answer.

chaise · Answer

Bring the 2/3 out the front of the integration and you are left with 1/sec(x-1) in the denominator with 1 in the numerator.

1/sec(x-1) = cos(x-1) 

integrate like normal. (make sure to bring the 2/3 out the front of the equation again)

you get: -2/3sin(1-x)+c

I do hope this is right. I've not yet mastered integration, but maybe this helped.

anonymous · Answer

yeah, I see what you're getting at. Thanks! let's master calc together ^^

anonymous · Answer

is this goes like this
put secx = 1/cosx and then q= integrate(2/3 (cosx/(1-cosx))
=2/3((1/(1-cosx)  -1 ) = 2/3  (1/2 cosec^x/2   -1)
on integration 
2/3 (-cotx/2 -x)  + c

chaise · Answer

or maybe I am wrong..................................

anonymous · Answer

thanks all. I know what I have to do now.

chaise · Answer

Okay :) Goodluck in future

anonymous · Answer

You too :)