Question

Please help! URGENT! Are the complex fractions (x^2-x-20)/(4)/(x-5)/(10) and (10)/(x-5)/(4)/(x^2-x-20) equivalent? Simplify each, and then explain why or why not.

Answer 1

They are equivalent. If you have (a/b)/(c/d) this is equivalent to (a*d)/(b*c). You can simplify and compare fractions from there.

Answer 2

Can you show me the work? please

Answer 3

\[((x^2-x-20)/4) / ((x-5) / 10)\] is the first fraction?

Answer 4

yeahh

Answer 5

This is equivalent to: ((x^2 - x - 20) / 4) * (10 / (x - 5))

Answer 6

Ohhh, cause you flip the second one right?

Answer 7

Apply the same simplification to the second fraction, and you should have two equivalent expressions.

Answer 8

Yes.

Answer 9

(a / b) / (c / d) = (a * d) / (b * c)

Answer 10

You can substitute each of the constants or expressions into the variables in the equation above.

Answer 11

hmmmm, I don't really get it. So it would be (x^2-x-20/ 4) (x-5 / 10) for the first part?

Answer 12

((x^2 - x - 20) / 4) * (10 / (x - 5)) for the first part.
(10 / (x - 5)) * ((x^2 - x - 20) / 4) for the second part.

Answer 13

And that's the answer? That's it?

Answer 14

In simple terms: Multiply the top by the bottom flipped upside down.
The answer is: Yes, they are equivalent.