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Mathematics 15 Online
OpenStudy (liliakarina):

What's the average for these data? a-X=194 b-X=190 c-X=28 d-X=12

OpenStudy (liliakarina):

I know I must get the sum of all elements and divide, but I don't get this!

Directrix (directrix):

Take the class average for each interval and multiply that by the frequency in that interval. The Mi for the first interval represents that interval and there are 2 scores there. So get the sum fo 142.5(2) + 66.5(9) + 190.5(28) + 214.5(19) + 238.5(2).

Directrix (directrix):

Check my numbers. Then, divide the sum by the sum of the frequencies which is 61. Does that make sense?

Directrix (directrix):

[142.5(2) + 166.5(9) + 190.5(28) + 214.5(19) + 238.5(2)] / 61 = 191.3

OpenStudy (liliakarina):

Okay, I will analyze it. I have a hard time understanding this part of Statistics, but your answer is very helpful :) Thanks!

Directrix (directrix):

Think of it this way. The average of a class interval is a value chosen to represent all data in that interval. So if we had an interval of 5 to 7 with 10 numbers in that interval that are data points, we let 6 represent all ten of them. Doing so loses their individual value.

OpenStudy (liliakarina):

You've made it easier, thanks!

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