Question

The total surface area of a right circular cylinder in which te height is twice the radius is 24pi sq. units. find the height.

Answer 1

SA=2(pi)*(r)*(height)

Answer 2

h = 2r

then




\[24\pi = 2\pi r^2 + 2\pi r \times 2r\]
divide by 2 pi
\[12 = r^2 + 2r^2\]
\[3r^2 =12\]
I'll let you finish the problem

Answer 3

oops should be

\[12 = 5r^2\]