Question

2cosx=2sinxcosx

Why?

Answer 1

it is possible when angle become 90.

Answer 2

Ok, new question. differentiate this with respect to x
\[\sin^2x\]

Answer 3

It involves this question

Answer 4

2sinxcosx.. ^_^

Answer 5

it equals 2sincos

Answer 6

Ok. How?

Answer 7

by rule of dervative

Answer 8

chain rule
u = sin x
du = cos x
f(u) = u^2
f'(u) = 2u

--> 2u*du = 2sincos

Answer 9

yeah.. rock . roll

Answer 10

Oh Ok. I thought you just switched the sin to cosin. But I guess, since it's squared... that rule doesn't apply fully.

Answer 11

u = (sinx)^n
f(u) = n(u)^(n-1)du