Question

Can someone help or teach me how to sketch the velocity and acceleration vectors in this problem(#5)

Answer 1

\[\vec r(t)=<cos(t),sin(t)>\]

velocity is just the derivative of position; it measures the rate of change in position at any given instant.

\[\vec r'(t)=<cos'(t),sin'(t)>\]
\[\vec r'(t)=<-sin(t),cos(t)>\]

Answer 2

acceleration is just the derivative of velocity; it measures the rate of change in speed at any given instant.\[\vec r'(t)=<-sin(t),cos(t)>\]
\[\vec r''(t)=<-cos(t),-sin(t)>\]

Answer 3

yes that is true, but i really need help with the sketching part

Answer 4

ill get to that ... first I have to make sure I write the problem out correctly; its my roadmap to success :)

Answer 5

now #5 gives us 2 times to fill in; since using one time would be pointless ....

Answer 6

im on the highway to hell

Answer 7

or is it heaven, dont know yet

Answer 8

so far

Answer 9

its a stairway to heaven and a highway to hell; and the buddha just sits under the bodhi tree watching the race ...

Answer 10

i prolly should input the ts to make sure ive got it going correctly

Answer 11

im a upload the answser wait a min

Answer 12

lol, I was getting there just backward

Answer 13

technology these days, you can just pull things right outta the sky

Answer 14

yep, but you can never trust the answers given in a book; they gots no proof :)

Answer 15

the proof, is in the pudding

Answer 16

i gotta go play clean up; the kids are messing the site up ...

Answer 17

I see what I did, I swapped out the sin and cos in the r(t) which made me go in the wrong direction ... otherwise its spot on :)